4+b=12/b

Solution for 4+b=12/b equation:

4+b=12/b

We move all terms to the left:

4+b-(12/b)=0


Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

b-(+12/b)+4=0

We get rid of parentheses

b-12/b+4=0

We multiply all the terms by the denominator


b*b+4*b-12=0

We add all the numbers together, and all the variables

4b+b*b-12=0

Wy multiply elements

b^2+4b-12=0

a = 1; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·1·(-12)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*1}=\frac{-12}{2}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*1}=\frac{4}{2}
=2
$