4+d=3d-13(d-2)

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Solution for 4+d=3d-13(d-2) equation: 



4+d=3d-13(d-2)

We move all terms to the left:

4+d-(3d-13(d-2))=0



We calculate terms in parentheses: -(3d-13(d-2)), so:

3d-13(d-2)

We multiply parentheses

3d-13d+26

We add all the numbers together, and all the variables

-10d+26

Back to the equation:

-(-10d+26)



We get rid of parentheses

d+10d-26+4=0

We add all the numbers together, and all the variables

11d-22=0

We move all terms containing d to the left, all other terms to the right

11d=22

d=22/11

d=2

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