4+i/2-i=y-i/x

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Solution for 4+i/2-i=y-i/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

i/2-i+4 = y-(i/x) // - y-(i/x)

i/2-i+i/x-y+4 = 0

i*x^-1 = -(4-1/2*i-y) // : i

x^-1 = -(i^-1*(4-1/2*i-y))

-1 < 0

1/(x^1) = -(i^-1*(4-1/2*i-y)) // * x^1

1 = -i^-1*x^1*(-(4-1/2*i-y)) // : -(i^-1*(4-1/2*i-y))

1/(-(i^-1*(4-1/2*i-y))) = x^1

x = 1/(-(i^-1*(4-1/2*i-y)))

x = 1/(-(i^-1*(4-1/2*i-y)))

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