4+x-2(x-3)=14(x-2)

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Solution for 4+x-2(x-3)=14(x-2) equation: 



4+x-2(x-3)=14(x-2)

We move all terms to the left:

4+x-2(x-3)-(14(x-2))=0

We multiply parentheses

x-2x-(14(x-2))+6+4=0



We calculate terms in parentheses: -(14(x-2)), so:

14(x-2)

We multiply parentheses

14x-28

Back to the equation:

-(14x-28)



We add all the numbers together, and all the variables

-1x-(14x-28)+10=0

We get rid of parentheses

-1x-14x+28+10=0

We add all the numbers together, and all the variables

-15x+38=0

We move all terms containing x to the left, all other terms to the right

-15x=-38

x=-38/-15

x=2+8/15

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