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4+x2=-9+2x
We move all terms to the left:
4+x2-(-9+2x)=0
We add all the numbers together, and all the variables
x2-(2x-9)+4=0
We add all the numbers together, and all the variables
x^2-(2x-9)+4=0
We get rid of parentheses
x^2-2x+9+4=0
We add all the numbers together, and all the variables
x^2-2x+13=0
a = 1; b = -2; c = +13;
Δ = b2-4ac
Δ = -22-4·1·13
Δ = -48
Delta is less than zero, so there is no solution for the equation
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