4+z-(3+2z)/6=-z-3(5-2)/7

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Solution for 4+z-(3+2z)/6=-z-3(5-2)/7 equation: 



4+z-(3+2z)/6=-z-3(5-2)/7

We move all terms to the left:

4+z-(3+2z)/6-(-z-3(5-2)/7)=0

We add all the numbers together, and all the variables

z-(2z+3)/6-(-z-33/7)+4=0

We get rid of parentheses

z-(2z+3)/6+z+4+33/7=0

We calculate fractions

There is no solution for this equation

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