4,2x2+21x+4=0

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Solution for 4,2x2+21x+4=0 equation:



4.2x^2+21x+4=0
a = 4.2; b = 21; c = +4;
Δ = b2-4ac
Δ = 212-4·4.2·4
Δ = 373.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{373.8}}{2*4.2}=\frac{-21-\sqrt{373.8}}{8.4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{373.8}}{2*4.2}=\frac{-21+\sqrt{373.8}}{8.4} $

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