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4.33x(38+x)=2400
We move all terms to the left:
4.33x(38+x)-(2400)=0
We add all the numbers together, and all the variables
4.33x(x+38)-2400=0
We multiply parentheses
4x^2+152x-2400=0
a = 4; b = 152; c = -2400;
Δ = b2-4ac
Δ = 1522-4·4·(-2400)
Δ = 61504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{61504}=248$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(152)-248}{2*4}=\frac{-400}{8} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(152)+248}{2*4}=\frac{96}{8} =12 $
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