4,9t2+2t-30=0

Solution for 4,9t2+2t-30=0 equation:

4.9t^2+2t-30=0

a = 4.9; b = 2; c = -30;
Δ = b2-4ac
Δ = 22-4·4.9·(-30)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{37}}{2*4.9}=\frac{-2-4\sqrt{37}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{37}}{2*4.9}=\frac{-2+4\sqrt{37}}{9.8}
$