4-(-7-6)=2(k+3)

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Solution for 4-(-7-6)=2(k+3) equation: 



4-(-7-6)=2(k+3)

We move all terms to the left:

4-(-7-6)-(2(k+3))=0

We add all the numbers together, and all the variables

-(2(k+3))+4-(-13)=0

We add all the numbers together, and all the variables

-(2(k+3))+17=0



We calculate terms in parentheses: -(2(k+3)), so:

2(k+3)

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We get rid of parentheses

-2k-6+17=0

We add all the numbers together, and all the variables

-2k+11=0

We move all terms containing k to the left, all other terms to the right

-2k=-11

k=-11/-2

k=5+1/2

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