4-(1/(v+1))=3/(v+2)

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Solution for 4-(1/(v+1))=3/(v+2) equation: 


D( v )

v+2 = 0

v+1 = 0

v+2 = 0

v+2 = 0

v+2 = 0 // - 2

v = -2

v+1 = 0

v+1 = 0

v+1 = 0 // - 1

v = -1

v in (-oo:-2) U (-2:-1) U (-1:+oo)

4-(1/(v+1)) = 3/(v+2) // - 3/(v+2)

4-(1/(v+1))-(3/(v+2)) = 0

4-(v+1)^-1-3*(v+2)^-1 = 0

4-1/(v+1)-3/(v+2) = 0

(-1*(v+2))/((v+1)*(v+2))+(-3*(v+1))/((v+1)*(v+2))+(4*(v+1)*(v+2))/((v+1)*(v+2)) = 0

4*(v+1)*(v+2)-1*(v+2)-3*(v+1) = 0

4*v^2-4*v+12*v-5+8 = 0

4*v^2+8*v+3 = 0

4*v^2+8*v+3 = 0

4*v^2+8*v+3 = 0

DELTA = 8^2-(3*4*4)

DELTA = 16

DELTA > 0

v = (16^(1/2)-8)/(2*4) or v = (-16^(1/2)-8)/(2*4)

v = -1/2 or v = -3/2

(v+3/2)*(v+1/2) = 0

((v+3/2)*(v+1/2))/((v+1)*(v+2)) = 0

((v+3/2)*(v+1/2))/((v+1)*(v+2)) = 0 // * (v+1)*(v+2)

(v+3/2)*(v+1/2) = 0

( v+1/2 )

v+1/2 = 0 // - 1/2

v = -1/2

( v+3/2 )

v+3/2 = 0 // - 3/2

v = -3/2

v in { -1/2, -3/2 }

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