4-(2k-3)+5=3(k-1)

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Solution for 4-(2k-3)+5=3(k-1) equation: 



4-(2k-3)+5=3(k-1)

We move all terms to the left:

4-(2k-3)+5-(3(k-1))=0

We add all the numbers together, and all the variables

-(2k-3)-(3(k-1))+9=0

We get rid of parentheses

-2k-(3(k-1))+3+9=0



We calculate terms in parentheses: -(3(k-1)), so:

3(k-1)

We multiply parentheses

3k-3

Back to the equation:

-(3k-3)



We add all the numbers together, and all the variables

-2k-(3k-3)+12=0

We get rid of parentheses

-2k-3k+3+12=0

We add all the numbers together, and all the variables

-5k+15=0

We move all terms containing k to the left, all other terms to the right

-5k=-15

k=-15/-5

k=+3

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