4-(2x+5)=(1/2)(-4x-2)

Solution for 4-(2x+5)=(1/2)(-4x-2) equation:

4-(2x+5)=(1/2)(-4x-2)

We move all terms to the left:

4-(2x+5)-((1/2)(-4x-2))=0


Domain of the equation: 2)(-4x-2))!=0

x∈R


We add all the numbers together, and all the variables

-(2x+5)-((+1/2)(-4x-2))+4=0

We get rid of parentheses

-2x-((+1/2)(-4x-2))-5+4=0

We multiply parentheses ..

-((-4x^2+1/2*-2))-2x-5+4=0

We multiply all the terms by the denominator


-((-4x^2+1-2x*2*-2))-5*2*-2))+4*2*-2))=0


We calculate terms in parentheses: -((-4x^2+1-2x*2*-2)), so:

(-4x^2+1-2x*2*-2)

We get rid of parentheses

-4x^2-2x*2*+1-2

We add all the numbers together, and all the variables

-4x^2-2x*2*-1

Wy multiply elements

-4x^2-4x^2-1

We add all the numbers together, and all the variables

-8x^2-1

Back to the equation:

-(-8x^2-1)


We add all the numbers together, and all the variables

-(-8x^2-1)=0

We get rid of parentheses

8x^2+1=0

a = 8; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·8·1
Δ = -32
Delta is less than zero, so there is no solution for the equation