4-(2z-8)/3=1/2(2z+5)

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Solution for 4-(2z-8)/3=1/2(2z+5) equation: 



4-(2z-8)/3=1/2(2z+5)

We move all terms to the left:

4-(2z-8)/3-(1/2(2z+5))=0



Domain of the equation: 2(2z+5))!=0

z∈R



We calculate fractions


(-(2z-8)*2(2z+5)))/(6z2+()/(6z2+4=0

We calculate fractions


((-(2z-8)*2(2z+5)))*(6z2+4)/((6z2*(6z2+4)+(()*6z2/((6z2*(6z2+4)=0



We calculate terms in parentheses: +((-(2z-8)*2(2z+5)))*(6z2+4)/((6z2*(6z2+4)+(()*6z2/((6z2*(6z2+4), so:

(-(2z-8)*2(2z+5)))*(6z2+4)/((6z2*(6z2+4)+(()*6z2/((6z2*(6z2+4

We can not solve this equation

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