4-(3/(w+1))=-3/(w+2)

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Solution for 4-(3/(w+1))=-3/(w+2) equation:


D( w )

w+1 = 0

w+2 = 0

w+1 = 0

w+1 = 0

w+1 = 0 // - 1

w = -1

w+2 = 0

w+2 = 0

w+2 = 0 // - 2

w = -2

w in (-oo:-2) U (-2:-1) U (-1:+oo)

4-(3/(w+1)) = -3/(w+2) // + -3/(w+2)

4-(3/(w+1))-(-3/(w+2)) = 0

3*(w+2)^-1-3*(w+1)^-1+4 = 0

3/(w+2)-3/(w+1)+4 = 0

(-3*(w+2))/((w+1)*(w+2))+(3*(w+1))/((w+1)*(w+2))+(4*(w+1)*(w+2))/((w+1)*(w+2)) = 0

3*(w+1)-3*(w+2)+4*(w+1)*(w+2) = 0

4*w^2+12*w-3+8 = 0

4*w^2+12*w+5 = 0

4*w^2+12*w+5 = 0

4*w^2+12*w+5 = 0

DELTA = 12^2-(4*4*5)

DELTA = 64

DELTA > 0

w = (64^(1/2)-12)/(2*4) or w = (-64^(1/2)-12)/(2*4)

w = -1/2 or w = -5/2

(w+5/2)*(w+1/2) = 0

((w+5/2)*(w+1/2))/((w+1)*(w+2)) = 0

((w+5/2)*(w+1/2))/((w+1)*(w+2)) = 0 // * (w+1)*(w+2)

(w+5/2)*(w+1/2) = 0

( w+1/2 )

w+1/2 = 0 // - 1/2

w = -1/2

( w+5/2 )

w+5/2 = 0 // - 5/2

w = -5/2

w in { -1/2, -5/2 }

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