4-(3a-5)=6-(2a+7)

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Solution for 4-(3a-5)=6-(2a+7) equation: 



4-(3a-5)=6-(2a+7)

We move all terms to the left:

4-(3a-5)-(6-(2a+7))=0

We get rid of parentheses

-3a-(6-(2a+7))+5+4=0



We calculate terms in parentheses: -(6-(2a+7)), so:

6-(2a+7)

determiningTheFunctionDomain
-(2a+7)+6

We get rid of parentheses

-2a-7+6

We add all the numbers together, and all the variables

-2a-1

Back to the equation:

-(-2a-1)



We add all the numbers together, and all the variables

-3a-(-2a-1)+9=0

We get rid of parentheses

-3a+2a+1+9=0

We add all the numbers together, and all the variables

-1a+10=0

We move all terms containing a to the left, all other terms to the right

-a=-10

a=-10/-1

a=+10

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