4-(3b-2)=b-10

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Solution for 4-(3b-2)=b-10 equation:


Simplifying
4 + -1(3b + -2) = b + -10

Reorder the terms:
4 + -1(-2 + 3b) = b + -10
4 + (-2 * -1 + 3b * -1) = b + -10
4 + (2 + -3b) = b + -10

Combine like terms: 4 + 2 = 6
6 + -3b = b + -10

Reorder the terms:
6 + -3b = -10 + b

Solving
6 + -3b = -10 + b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
6 + -3b + -1b = -10 + b + -1b

Combine like terms: -3b + -1b = -4b
6 + -4b = -10 + b + -1b

Combine like terms: b + -1b = 0
6 + -4b = -10 + 0
6 + -4b = -10

Add '-6' to each side of the equation.
6 + -6 + -4b = -10 + -6

Combine like terms: 6 + -6 = 0
0 + -4b = -10 + -6
-4b = -10 + -6

Combine like terms: -10 + -6 = -16
-4b = -16

Divide each side by '-4'.
b = 4

Simplifying
b = 4

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