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4-(3h+2)=1-(5-5h)
We move all terms to the left:
4-(3h+2)-(1-(5-5h))=0
We add all the numbers together, and all the variables
-(3h+2)-(1-(-5h+5))+4=0
We get rid of parentheses
-3h-(1-(-5h+5))-2+4=0
We calculate terms in parentheses: -(1-(-5h+5)), so:We add all the numbers together, and all the variables
1-(-5h+5)
determiningTheFunctionDomain -(-5h+5)+1
We get rid of parentheses
5h-5+1
We add all the numbers together, and all the variables
5h-4
Back to the equation:
-(5h-4)
-3h-(5h-4)+2=0
We get rid of parentheses
-3h-5h+4+2=0
We add all the numbers together, and all the variables
-8h+6=0
We move all terms containing h to the left, all other terms to the right
-8h=-6
h=-6/-8
h=3/4
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