4-(3n-5)=6-(2n+7)

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Solution for 4-(3n-5)=6-(2n+7) equation: 



4-(3n-5)=6-(2n+7)

We move all terms to the left:

4-(3n-5)-(6-(2n+7))=0

We get rid of parentheses

-3n-(6-(2n+7))+5+4=0



We calculate terms in parentheses: -(6-(2n+7)), so:

6-(2n+7)

determiningTheFunctionDomain
-(2n+7)+6

We get rid of parentheses

-2n-7+6

We add all the numbers together, and all the variables

-2n-1

Back to the equation:

-(-2n-1)



We add all the numbers together, and all the variables

-3n-(-2n-1)+9=0

We get rid of parentheses

-3n+2n+1+9=0

We add all the numbers together, and all the variables

-1n+10=0

We move all terms containing n to the left, all other terms to the right

-n=-10

n=-10/-1

n=+10

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