4-(3n-5)=6-(2n+7)

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Solution for 4-(3n-5)=6-(2n+7) equation:



4-(3n-5)=6-(2n+7)
We move all terms to the left:
4-(3n-5)-(6-(2n+7))=0
We get rid of parentheses
-3n-(6-(2n+7))+5+4=0
We calculate terms in parentheses: -(6-(2n+7)), so:
6-(2n+7)
determiningTheFunctionDomain -(2n+7)+6
We get rid of parentheses
-2n-7+6
We add all the numbers together, and all the variables
-2n-1
Back to the equation:
-(-2n-1)
We add all the numbers together, and all the variables
-3n-(-2n-1)+9=0
We get rid of parentheses
-3n+2n+1+9=0
We add all the numbers together, and all the variables
-1n+10=0
We move all terms containing n to the left, all other terms to the right
-n=-10
n=-10/-1
n=+10

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