4-(5x-1)(2x+3)=17-(10x+2)(x+6)

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Solution for 4-(5x-1)(2x+3)=17-(10x+2)(x+6) equation: 



4-(5x-1)(2x+3)=17-(10x+2)(x+6)

We move all terms to the left:

4-(5x-1)(2x+3)-(17-(10x+2)(x+6))=0

We multiply parentheses ..

-(+10x^2+15x-2x-3)-(17-(10x+2)(x+6))+4=0



We calculate terms in parentheses: -(17-(10x+2)(x+6)), so:

17-(10x+2)(x+6)

determiningTheFunctionDomain
-(10x+2)(x+6)+17

We multiply parentheses ..

-(+10x^2+60x+2x+12)+17

We get rid of parentheses

-10x^2-60x-2x-12+17

We add all the numbers together, and all the variables

-10x^2-62x+5

Back to the equation:

-(-10x^2-62x+5)



We get rid of parentheses

-10x^2+10x^2-15x+2x+62x+3-5+4=0

We add all the numbers together, and all the variables

49x+2=0

We move all terms containing x to the left, all other terms to the right

49x=-2

x=-2/49

x=-2/49

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