4-(6x+3)=12x+(2x+44)

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Solution for 4-(6x+3)=12x+(2x+44) equation: 



4-(6x+3)=12x+(2x+44)

We move all terms to the left:

4-(6x+3)-(12x+(2x+44))=0

We get rid of parentheses

-6x-(12x+(2x+44))-3+4=0



We calculate terms in parentheses: -(12x+(2x+44)), so:

12x+(2x+44)

We get rid of parentheses

12x+2x+44

We add all the numbers together, and all the variables

14x+44

Back to the equation:

-(14x+44)



We add all the numbers together, and all the variables

-6x-(14x+44)+1=0

We get rid of parentheses

-6x-14x-44+1=0

We add all the numbers together, and all the variables

-20x-43=0

We move all terms containing x to the left, all other terms to the right

-20x=43

x=43/-20

x=-2+3/20

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