4-(b+1)+2b=3(2b-1)

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Solution for 4-(b+1)+2b=3(2b-1) equation: 



4-(b+1)+2b=3(2b-1)

We move all terms to the left:

4-(b+1)+2b-(3(2b-1))=0

We add all the numbers together, and all the variables

2b-(b+1)-(3(2b-1))+4=0

We get rid of parentheses

2b-b-(3(2b-1))-1+4=0



We calculate terms in parentheses: -(3(2b-1)), so:

3(2b-1)

We multiply parentheses

6b-3

Back to the equation:

-(6b-3)



We add all the numbers together, and all the variables

b-(6b-3)+3=0

We get rid of parentheses

b-6b+3+3=0

We add all the numbers together, and all the variables

-5b+6=0

We move all terms containing b to the left, all other terms to the right

-5b=-6

b=-6/-5

b=1+1/5

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