4-(b-3)+3(b+4)=7

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Solution for 4-(b-3)+3(b+4)=7 equation: 


Simplifying
4 + -1(b + -3) + 3(b + 4) = 7

Reorder the terms:
4 + -1(-3 + b) + 3(b + 4) = 7
4 + (-3 * -1 + b * -1) + 3(b + 4) = 7
4 + (3 + -1b) + 3(b + 4) = 7

Reorder the terms:
4 + 3 + -1b + 3(4 + b) = 7
4 + 3 + -1b + (4 * 3 + b * 3) = 7
4 + 3 + -1b + (12 + 3b) = 7

Reorder the terms:
4 + 3 + 12 + -1b + 3b = 7

Combine like terms: 4 + 3 = 7
7 + 12 + -1b + 3b = 7

Combine like terms: 7 + 12 = 19
19 + -1b + 3b = 7

Combine like terms: -1b + 3b = 2b
19 + 2b = 7

Solving
19 + 2b = 7

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 2b = 7 + -19

Combine like terms: 19 + -19 = 0
0 + 2b = 7 + -19
2b = 7 + -19

Combine like terms: 7 + -19 = -12
2b = -12

Divide each side by '2'.
b = -6

Simplifying
b = -6

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