4-(m+3)-4m+5=m-18

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Solution for 4-(m+3)-4m+5=m-18 equation: 



4-(m+3)-4m+5=m-18

We move all terms to the left:

4-(m+3)-4m+5-(m-18)=0

We add all the numbers together, and all the variables

-4m-(m+3)-(m-18)+9=0

We get rid of parentheses

-4m-m-m-3+18+9=0

We add all the numbers together, and all the variables

-6m+24=0

We move all terms containing m to the left, all other terms to the right

-6m=-24

m=-24/-6

m=+4

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