4-(n-26)=5(n+5)

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Solution for 4-(n-26)=5(n+5) equation: 



4-(n-26)=5(n+5)

We move all terms to the left:

4-(n-26)-(5(n+5))=0

We get rid of parentheses

-n-(5(n+5))+26+4=0



We calculate terms in parentheses: -(5(n+5)), so:

5(n+5)

We multiply parentheses

5n+25

Back to the equation:

-(5n+25)



We add all the numbers together, and all the variables

-1n-(5n+25)+30=0

We get rid of parentheses

-1n-5n-25+30=0

We add all the numbers together, and all the variables

-6n+5=0

We move all terms containing n to the left, all other terms to the right

-6n=-5

n=-5/-6

n=5/6

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