4-(x+2)(x+2)=0

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Solution for 4-(x+2)(x+2)=0 equation:


Simplifying
4 + -1(x + 2)(x + 2) = 0

Reorder the terms:
4 + -1(2 + x)(x + 2) = 0

Reorder the terms:
4 + -1(2 + x)(2 + x) = 0

Multiply (2 + x) * (2 + x)
4 + -1(2(2 + x) + x(2 + x)) = 0
4 + -1((2 * 2 + x * 2) + x(2 + x)) = 0
4 + -1((4 + 2x) + x(2 + x)) = 0
4 + -1(4 + 2x + (2 * x + x * x)) = 0
4 + -1(4 + 2x + (2x + x2)) = 0

Combine like terms: 2x + 2x = 4x
4 + -1(4 + 4x + x2) = 0
4 + (4 * -1 + 4x * -1 + x2 * -1) = 0
4 + (-4 + -4x + -1x2) = 0

Combine like terms: 4 + -4 = 0
0 + -4x + -1x2 = 0
-4x + -1x2 = 0

Solving
-4x + -1x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '-1x'.
-1x(4 + x) = 0

Ignore the factor -1.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Solution

x = {0, -4}

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