4-(x+2)=(1/3)(5x-1)

Solution for 4-(x+2)=(1/3)(5x-1) equation:

4-(x+2)=(1/3)(5x-1)

We move all terms to the left:

4-(x+2)-((1/3)(5x-1))=0


Domain of the equation: 3)(5x-1))!=0

x∈R


We add all the numbers together, and all the variables

-(x+2)-((+1/3)(5x-1))+4=0

We get rid of parentheses

-x-((+1/3)(5x-1))-2+4=0

We multiply parentheses ..

-((+5x^2+1/3*-1))-x-2+4=0

We multiply all the terms by the denominator


-((+5x^2+1-x*3*-1))-2*3*-1))+4*3*-1))=0


We calculate terms in parentheses: -((+5x^2+1-x*3*-1)), so:

(+5x^2+1-x*3*-1)

We get rid of parentheses

5x^2-x*3*+1-1

We add all the numbers together, and all the variables

5x^2-x*3*

Wy multiply elements

5x^2-3x^2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

-(2x^2)


We add all the numbers together, and all the variables

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$