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4-(x+2)=5+(3x-1)
We move all terms to the left:
4-(x+2)-(5+(3x-1))=0
We get rid of parentheses
-x-(5+(3x-1))-2+4=0
We calculate terms in parentheses: -(5+(3x-1)), so:We add all the numbers together, and all the variables
5+(3x-1)
determiningTheFunctionDomain (3x-1)+5
We get rid of parentheses
3x-1+5
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
-1x-(3x+4)+2=0
We get rid of parentheses
-1x-3x-4+2=0
We add all the numbers together, and all the variables
-4x-2=0
We move all terms containing x to the left, all other terms to the right
-4x=2
x=2/-4
x=-1/2
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