4-(x+3)=8-5(2x-3)=

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Solution for 4-(x+3)=8-5(2x-3)= equation: 



4-(x+3)=8-5(2x-3)=

We move all terms to the left:

4-(x+3)-(8-5(2x-3))=0

We get rid of parentheses

-x-(8-5(2x-3))-3+4=0



We calculate terms in parentheses: -(8-5(2x-3)), so:

8-5(2x-3)

determiningTheFunctionDomain
-5(2x-3)+8

We multiply parentheses

-10x+15+8

We add all the numbers together, and all the variables

-10x+23

Back to the equation:

-(-10x+23)



We add all the numbers together, and all the variables

-1x-(-10x+23)+1=0

We get rid of parentheses

-1x+10x-23+1=0

We add all the numbers together, and all the variables

9x-22=0

We move all terms containing x to the left, all other terms to the right

9x=22

x=22/9

x=2+4/9

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