4-(x-4)=x(3-5)+2+4

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Solution for 4-(x-4)=x(3-5)+2+4 equation: 



4-(x-4)=x(3-5)+2+4

We move all terms to the left:

4-(x-4)-(x(3-5)+2+4)=0

We add all the numbers together, and all the variables

-(x-4)-(x(-2)+2+4)+4=0

We get rid of parentheses

-x-(x(-2)+2+4)+4+4=0



We calculate terms in parentheses: -(x(-2)+2+4), so:

x(-2)+2+4

We add all the numbers together, and all the variables

x(-2)+6

We multiply parentheses

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

-1x-(-2x+6)+8=0

We get rid of parentheses

-1x+2x-6+8=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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