4-(x2+x-2)=8-x2

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Solution for 4-(x2+x-2)=8-x2 equation:



4-(x2+x-2)=8-x2
We move all terms to the left:
4-(x2+x-2)-(8-x2)=0
We add all the numbers together, and all the variables
-(+x^2+x-2)-(-1x^2+8)+4=0
We get rid of parentheses
-x^2+1x^2-x+2-8+4=0
We add all the numbers together, and all the variables
-1x-2=0
We move all terms containing x to the left, all other terms to the right
-x=2
x=2/-1
x=-2

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