4-(y+3)+(2y+2)=

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Solution for 4-(y+3)+(2y+2)= equation:


Simplifying
4 + -1(y + 3) + (2y + 2) = 0

Reorder the terms:
4 + -1(3 + y) + (2y + 2) = 0
4 + (3 * -1 + y * -1) + (2y + 2) = 0
4 + (-3 + -1y) + (2y + 2) = 0

Reorder the terms:
4 + -3 + -1y + (2 + 2y) = 0

Remove parenthesis around (2 + 2y)
4 + -3 + -1y + 2 + 2y = 0

Reorder the terms:
4 + -3 + 2 + -1y + 2y = 0

Combine like terms: 4 + -3 = 1
1 + 2 + -1y + 2y = 0

Combine like terms: 1 + 2 = 3
3 + -1y + 2y = 0

Combine like terms: -1y + 2y = 1y
3 + 1y = 0

Solving
3 + 1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 1y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 1y = 0 + -3
1y = 0 + -3

Combine like terms: 0 + -3 = -3
1y = -3

Divide each side by '1'.
y = -3

Simplifying
y = -3

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