4-(y-5)-y+3=2

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Solution for 4-(y-5)-y+3=2 equation: 



4-(y-5)-y+3=2

We move all terms to the left:

4-(y-5)-y+3-(2)=0

We add all the numbers together, and all the variables

-1y-(y-5)+5=0

We get rid of parentheses

-1y-y+5+5=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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