4-(z-12)=42

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Solution for 4-(z-12)=42 equation:



4-(z-12)=42
We move all terms to the left:
4-(z-12)-(42)=0
We add all the numbers together, and all the variables
-(z-12)-38=0
We get rid of parentheses
-z+12-38=0
We add all the numbers together, and all the variables
-1z-26=0
We move all terms containing z to the left, all other terms to the right
-z=26
z=26/-1
z=-26

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