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4-1(2x+1)/2=1+1(x-1)/5
We move all terms to the left:
4-1(2x+1)/2-(1+1(x-1)/5)=0
We calculate fractions
(-1(2x+1)*5))/()+(-(1+1(x-1)*2)/()+4=0
We calculate terms in parentheses: -(1+1(x-1)*2)/(), so:We add all the numbers together, and all the variables
1+1(x-1)*2)/(
determiningTheFunctionDomain 1(x-1)*2)/(+1
We multiply all the terms by the denominator
1(x-1)*2)+1*(
Back to the equation:
-(1(x-1)*2)+1*()
(-1(2x+1)*5))/()+(-(1(x-1)*2)=0
We multiply all the terms by the denominator
(-1(2x+1)*5))-((1(x-1)*2))*()+(=0
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