4-1/3z=7z+6

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Solution for 4-1/3z=7z+6 equation: 



4-1/3z=7z+6

We move all terms to the left:

4-1/3z-(7z+6)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We get rid of parentheses

-1/3z-7z-6+4=0

We multiply all the terms by the denominator


-7z*3z-6*3z+4*3z-1=0

Wy multiply elements

-21z^2-18z+12z-1=0

We add all the numbers together, and all the variables

-21z^2-6z-1=0

a = -21; b = -6; c = -1;
Δ = b2-4ac
Δ = -62-4·(-21)·(-1)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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