4-10(3n-2)=-6(n+8)

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Solution for 4-10(3n-2)=-6(n+8) equation: 



4-10(3n-2)=-6(n+8)

We move all terms to the left:

4-10(3n-2)-(-6(n+8))=0

We multiply parentheses

-30n-(-6(n+8))+20+4=0



We calculate terms in parentheses: -(-6(n+8)), so:

-6(n+8)

We multiply parentheses

-6n-48

Back to the equation:

-(-6n-48)



We add all the numbers together, and all the variables

-30n-(-6n-48)+24=0

We get rid of parentheses

-30n+6n+48+24=0

We add all the numbers together, and all the variables

-24n+72=0

We move all terms containing n to the left, all other terms to the right

-24n=-72

n=-72/-24

n=+3

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