4-10/a=3+4a

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Solution for 4-10/a=3+4a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

4-(10/a) = 4*a+3 // - 4*a+3

4-(4*a)-(10/a)-3 = 0

4-4*a-10*a^-1-3 = 0

1*a^0-4*a^1-10*a^-1 = 0

(1*a^1-4*a^2-10*a^0)/(a^1) = 0 // * a^2

a^1*(1*a^1-4*a^2-10*a^0) = 0

a^1

a-4*a^2-10 = 0

a-4*a^2-10 = 0

DELTA = 1^2-(-10*(-4)*4)

DELTA = -159

DELTA < 0

a in { } 

a belongs to the empty set

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