4-2(20c+2)=-80

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Solution for 4-2(20c+2)=-80 equation: 



4-2(20c+2)=-80

We move all terms to the left:

4-2(20c+2)-(-80)=0

We add all the numbers together, and all the variables

-2(20c+2)+84=0

We multiply parentheses

-40c-4+84=0

We add all the numbers together, and all the variables

-40c+80=0

We move all terms containing c to the left, all other terms to the right

-40c=-80

c=-80/-40

c=+2

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