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4-2(3-2x)=3(x-4)
We move all terms to the left:
4-2(3-2x)-(3(x-4))=0
We add all the numbers together, and all the variables
-2(-2x+3)-(3(x-4))+4=0
We multiply parentheses
4x-(3(x-4))-6+4=0
We calculate terms in parentheses: -(3(x-4)), so:We add all the numbers together, and all the variables
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
4x-(3x-12)-2=0
We get rid of parentheses
4x-3x+12-2=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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