4-2(3x+1)=6(4+x)

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Solution for 4-2(3x+1)=6(4+x) equation: 



4-2(3x+1)=6(4+x)

We move all terms to the left:

4-2(3x+1)-(6(4+x))=0

We add all the numbers together, and all the variables

-2(3x+1)-(6(x+4))+4=0

We multiply parentheses

-6x-(6(x+4))-2+4=0



We calculate terms in parentheses: -(6(x+4)), so:

6(x+4)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We add all the numbers together, and all the variables

-6x-(6x+24)+2=0

We get rid of parentheses

-6x-6x-24+2=0

We add all the numbers together, and all the variables

-12x-22=0

We move all terms containing x to the left, all other terms to the right

-12x=22

x=22/-12

x=-1+5/6

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