4-2(3x-4)=2(4x+1)

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Solution for 4-2(3x-4)=2(4x+1) equation: 



4-2(3x-4)=2(4x+1)

We move all terms to the left:

4-2(3x-4)-(2(4x+1))=0

We multiply parentheses

-6x-(2(4x+1))+8+4=0



We calculate terms in parentheses: -(2(4x+1)), so:

2(4x+1)

We multiply parentheses

8x+2

Back to the equation:

-(8x+2)



We add all the numbers together, and all the variables

-6x-(8x+2)+12=0

We get rid of parentheses

-6x-8x-2+12=0

We add all the numbers together, and all the variables

-14x+10=0

We move all terms containing x to the left, all other terms to the right

-14x=-10

x=-10/-14

x=5/7

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