4-2(3z+1)=32

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Solution for 4-2(3z+1)=32 equation:



4-2(3z+1)=32
We move all terms to the left:
4-2(3z+1)-(32)=0
We add all the numbers together, and all the variables
-2(3z+1)-28=0
We multiply parentheses
-6z-2-28=0
We add all the numbers together, and all the variables
-6z-30=0
We move all terms containing z to the left, all other terms to the right
-6z=30
z=30/-6
z=-5

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