4-2(b-3)=20

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Solution for 4-2(b-3)=20 equation: 



4-2(b-3)=20

We move all terms to the left:

4-2(b-3)-(20)=0

We add all the numbers together, and all the variables

-2(b-3)-16=0

We multiply parentheses

-2b+6-16=0

We add all the numbers together, and all the variables

-2b-10=0

We move all terms containing b to the left, all other terms to the right

-2b=10

b=10/-2

b=-5

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