4-2(t-5)=3t-4(t+2)

Solution for 4-2(t-5)=3t-4(t+2) equation:

4-2(t-5)=3t-4(t+2)

We move all terms to the left:

4-2(t-5)-(3t-4(t+2))=0

We multiply parentheses

-2t-(3t-4(t+2))+10+4=0


We calculate terms in parentheses: -(3t-4(t+2)), so:

3t-4(t+2)

We multiply parentheses

3t-4t-8

We add all the numbers together, and all the variables

-1t-8

Back to the equation:

-(-1t-8)


We add all the numbers together, and all the variables

-2t-(-1t-8)+14=0

We get rid of parentheses

-2t+1t+8+14=0

We add all the numbers together, and all the variables

-1t+22=0

We move all terms containing t to the left, all other terms to the right

-t=-22

t=-22/-1

t=+22