4-2(x+3)=x-5+6x

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Solution for 4-2(x+3)=x-5+6x equation: 



4-2(x+3)=x-5+6x

We move all terms to the left:

4-2(x+3)-(x-5+6x)=0

We add all the numbers together, and all the variables

-2(x+3)-(7x-5)+4=0

We multiply parentheses

-2x-(7x-5)-6+4=0

We get rid of parentheses

-2x-7x+5-6+4=0

We add all the numbers together, and all the variables

-9x+3=0

We move all terms containing x to the left, all other terms to the right

-9x=-3

x=-3/-9

x=1/3

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