4-2(x+3)=x-5+6x

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Solution for 4-2(x+3)=x-5+6x equation:



4-2(x+3)=x-5+6x
We move all terms to the left:
4-2(x+3)-(x-5+6x)=0
We add all the numbers together, and all the variables
-2(x+3)-(7x-5)+4=0
We multiply parentheses
-2x-(7x-5)-6+4=0
We get rid of parentheses
-2x-7x+5-6+4=0
We add all the numbers together, and all the variables
-9x+3=0
We move all terms containing x to the left, all other terms to the right
-9x=-3
x=-3/-9
x=1/3

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