4-2(x-3)=2-3(x+1)

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Solution for 4-2(x-3)=2-3(x+1) equation: 



4-2(x-3)=2-3(x+1)

We move all terms to the left:

4-2(x-3)-(2-3(x+1))=0

We multiply parentheses

-2x-(2-3(x+1))+6+4=0



We calculate terms in parentheses: -(2-3(x+1)), so:

2-3(x+1)

determiningTheFunctionDomain
-3(x+1)+2

We multiply parentheses

-3x-3+2

We add all the numbers together, and all the variables

-3x-1

Back to the equation:

-(-3x-1)



We add all the numbers together, and all the variables

-2x-(-3x-1)+10=0

We get rid of parentheses

-2x+3x+1+10=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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