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4-2(x-3)=2-3(x+1)
We move all terms to the left:
4-2(x-3)-(2-3(x+1))=0
We multiply parentheses
-2x-(2-3(x+1))+6+4=0
We calculate terms in parentheses: -(2-3(x+1)), so:We add all the numbers together, and all the variables
2-3(x+1)
determiningTheFunctionDomain -3(x+1)+2
We multiply parentheses
-3x-3+2
We add all the numbers together, and all the variables
-3x-1
Back to the equation:
-(-3x-1)
-2x-(-3x-1)+10=0
We get rid of parentheses
-2x+3x+1+10=0
We add all the numbers together, and all the variables
x+11=0
We move all terms containing x to the left, all other terms to the right
x=-11
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