4-2(x-3)=x-5(x+1)

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Solution for 4-2(x-3)=x-5(x+1) equation: 



4-2(x-3)=x-5(x+1)

We move all terms to the left:

4-2(x-3)-(x-5(x+1))=0

We multiply parentheses

-2x-(x-5(x+1))+6+4=0



We calculate terms in parentheses: -(x-5(x+1)), so:

x-5(x+1)

We multiply parentheses

x-5x-5

We add all the numbers together, and all the variables

-4x-5

Back to the equation:

-(-4x-5)



We add all the numbers together, and all the variables

-2x-(-4x-5)+10=0

We get rid of parentheses

-2x+4x+5+10=0

We add all the numbers together, and all the variables

2x+15=0

We move all terms containing x to the left, all other terms to the right

2x=-15

x=-15/2

x=-7+1/2

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