4-2(x-5)=x+41

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Solution for 4-2(x-5)=x+41 equation: 



4-2(x-5)=x+41

We move all terms to the left:

4-2(x-5)-(x+41)=0

We multiply parentheses

-2x-(x+41)+10+4=0

We get rid of parentheses

-2x-x-41+10+4=0

We add all the numbers together, and all the variables

-3x-27=0

We move all terms containing x to the left, all other terms to the right

-3x=27

x=27/-3

x=-9

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