4-2(y+1)=4(3y-2)

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Solution for 4-2(y+1)=4(3y-2) equation: 



4-2(y+1)=4(3y-2)

We move all terms to the left:

4-2(y+1)-(4(3y-2))=0

We multiply parentheses

-2y-(4(3y-2))-2+4=0



We calculate terms in parentheses: -(4(3y-2)), so:

4(3y-2)

We multiply parentheses

12y-8

Back to the equation:

-(12y-8)



We add all the numbers together, and all the variables

-2y-(12y-8)+2=0

We get rid of parentheses

-2y-12y+8+2=0

We add all the numbers together, and all the variables

-14y+10=0

We move all terms containing y to the left, all other terms to the right

-14y=-10

y=-10/-14

y=5/7

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